Formulas
Formula substitution forms the foundation of GCSE maths problem-solving, appearing in 15% of Foundation tier questions and 25% of Higher tier papers. Students must master replacing letters with numbers across physics formulas, area calculations, and algebraic expressions to succeed in Year 11 assessments.
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Why it matters
Formula substitution connects abstract algebra to real-world problem solving across multiple GCSE subjects. In physics, students calculate velocity using v = u + at to analyse car acceleration from 0 to 30 mph in 8 seconds. Geography students apply population density formulas when examining London's 9,648 people per square kilometre. Business studies requires profit calculations using P = R - C with revenues of £50,000 and costs of £32,000. Engineering students substitute into stress formulas σ = F/A with forces of 2,500 N acting on areas of 25 cm². These applications demonstrate why 78% of GCSE science questions require formula manipulation, making substitution skills essential for academic progression and career readiness in STEM fields.
How to solve formulas
Substitution into Formulas
- Identify which variable each value replaces.
- Substitute (replace) the letters with the given numbers.
- Follow order of operations (PEMDAS) to evaluate.
- Include units in your final answer if applicable.
Example: A = πr². If r = 4: A = π(16) ≈ 50.3.
Worked examples
If speed = distance ÷ time, and distance = 600 km, time = 5 hours, find speed.
Answer: 120 km/h
- Write the formula → speed = distance ÷ time — Use the given formula.
- Substitute the values → speed = 600 ÷ 5 — Replace distance with 600 and time with 5.
- Calculate → 120 km/h — 600 ÷ 5 = 120.
If A = l × w, l = 11, w = 6, find A.
Answer: 66
- Write the formula → A = l × w — Area equals length times width.
- Substitute the values → A = 11 × 6 — Replace l with 11 and w with 6.
- Calculate → 66 — 11 × 6 = 66.
If v = u + at, u = 5, a = 10, t = 5, find v.
Answer: 55
- Write the formula → v = u + at — Final velocity equals initial velocity plus acceleration times time.
- Substitute the values → v = 5 + 10 × 5 — Replace u with 5, a with 10, t with 5.
- Calculate at → 10 × 5 = 50 — Multiply acceleration by time: 10 × 5 = 50.
- Add → v = 55 — 5 + 50 = 55.
Common mistakes
- Students substitute incorrectly by writing v = 5 + 10 + 5 = 20 instead of v = 5 + (10 × 5) = 55, forgetting that multiplication comes before addition in the order of operations.
- When rearranging v = u + at to find t, students write t = v - u ÷ a = 15 - 5 ÷ 2 = 10 ÷ 2 = 5 instead of t = (v - u) ÷ a = (15 - 5) ÷ 2 = 5.
- Students mix up variables by substituting l = 8 and w = 6 into A = l × w as A = 6 × 8 instead of maintaining the correct order A = 8 × 6.
- When calculating speed = distance ÷ time with distance 120 km and time 3 hours, students write 3 ÷ 120 = 0.025 instead of 120 ÷ 3 = 40 km/h.