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Trigonometric Equations

CCSS.HSF.TF.B.7LK20.R1.trigonometriske_likningerLK20.R2.trigonometriske_likninger3 min read

Trigonometric equations challenge students to combine unit circle knowledge with algebraic problem-solving skills. These equations appear frequently on standardized tests and form the foundation for advanced calculus concepts.

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Why it matters

Trigonometric equations model real-world phenomena from engineering to physics. AC electrical circuits use equations like sin(120Ο€t) = 0.5 to determine when voltage reaches specific values. Sound engineers solve cos(2Ο€ft) = -0.707 to find phase relationships in audio mixing. Architecture students use tan(ΞΈ) = 23 to calculate optimal roof angles for specific drainage requirements. Weather forecasters analyze temperature patterns using equations like sin(Ο€t/12) = 0.866 to predict daily highs. CCSS.HSF.TF.B.7 and LK20 trigonometric equations standards emphasize these practical applications, ensuring students can transition from abstract unit circle values to solving complex real-world problems involving periodic functions.

How to solve trigonometric equations

Trig Equations

  • Isolate the trig function: e.g. sin x = v.
  • Find the reference angle from the unit circle.
  • Use ASTC to list all solutions in the required interval [0, 2Ο€) or [0Β°, 360Β°).
  • For sin(kx) = v, solve for kx first, then divide. Remember the period.

Example: 2 sin x = 1 β†’ sin x = 12 β†’ x = Ο€/6 or 5Ο€/6 in [0, 2Ο€).

Worked examples

Beginner

Solve cos(x) = βˆ’βˆš32 on the interval [0Β°, 360Β°].

Answer: 150Β°, 210Β°

  1. Identify the reference angle from the unit circle β†’ cos(reference) = √3/2 β€” Start with the positive version of the value and find the acute angle whose sin/cos/tan equals it. That's the reference angle.
  2. Find every angle in [0Β°, 360Β°] with the correct sign β†’ x ∈ {150Β°, 210Β°} β€” Use ASTC to determine which quadrants give the desired sign. Each quadrant gives one solution (or two for the axial angles 0Β°, 90Β°, 180Β°, 270Β°, 360Β°).
Easy

Solve cos(x) = βˆ’1 on the interval [0, 2Ο€].

Answer: Ο€

  1. Find the reference angle in radians β†’ reference angle from unit circle β€” The standard reference values in radians are Ο€/6, Ο€/4, Ο€/3, Ο€/2. Pick the one whose sin/cos/tan matches the absolute value of the right-hand side.
  2. List every solution in [0, 2Ο€] β†’ x ∈ {Ο€} β€” Apply ASTC to pick the right quadrants, then convert each to its radian form.
Medium

Solve cos(2x) = βˆ’βˆš22 on the interval [0, 2Ο€].

Answer: 3Ο€/8, 5Ο€/8, 11Ο€/8, 13Ο€/8

  1. Substitute u = 2x and find the new interval for u β†’ u ∈ [0, 4Ο€] β€” Since x ∈ [0, 2Ο€] and u = 2x, the interval for u is [0, 4Ο€] β€” 2 times longer, so expect 2Γ— as many solutions as the standard equation.
  2. Solve cos(u) = βˆ’βˆš2/2 and divide each solution by 2 β†’ x ∈ {3Ο€/8, 5Ο€/8, 11Ο€/8, 13Ο€/8} β€” Find the base solutions, add 2Ο€ each time to stay in the longer interval, then divide by the coefficient.

Common mistakes

  • βœ—Students find only one solution when multiple exist, writing cos(x) = 1/2 gives x = Ο€/3 instead of x = Ο€/3, 5Ο€/3 in [0, 2Ο€]
  • βœ—Forgetting to expand the interval for multi-angle equations, solving cos(2x) = 1/2 over [0, 2Ο€] but missing solutions like 11Ο€/6
  • βœ—Mixing up reference angles and actual solutions, writing sin(x) = -√2/2 gives x = Ο€/4 instead of x = 5Ο€/4, 7Ο€/4
  • βœ—Using degrees when radians are required, writing cos(x) = √3/2 gives x = 30Β° instead of x = Ο€/6 when interval is [0, 2Ο€]

Practice on your own

Generate unlimited trigonometric equation practice problems with step-by-step solutions using MathAnvil's free worksheet creator.

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Frequently asked questions

How do I handle equations like sin(3x) = 1/2?β–Ύ
Substitute u = 3x and solve sin(u) = 1/2 first. Since x ∈ [0, 2Ο€], then u ∈ [0, 6Ο€]. Find all solutions for u, then divide each by 3 to get x-values. This gives 6 solutions instead of the usual 2.
What's the difference between solving in degrees versus radians?β–Ύ
The process is identical, but intervals change. [0Β°, 360Β°] becomes [0, 2Ο€]. Reference angles shift: 30Β° becomes Ο€/6, 45Β° becomes Ο€/4, 60Β° becomes Ο€/3. Students must match their answer format to the question's units.
How do I solve quadratic trigonometric equations?β–Ύ
Treat the trig function as a variable. For 2sinΒ²(x) - sin(x) - 1 = 0, let u = sin(x), giving 2uΒ² - u - 1 = 0. Factor to get (2u + 1)(u - 1) = 0, so u = -1/2 or u = 1. Then solve sin(x) = -1/2 and sin(x) = 1 separately.
Why do some equations have no solutions?β–Ύ
Trigonometric functions have restricted ranges: sin(x) and cos(x) only produce values between -1 and 1, tan(x) produces all real values. Equations like sin(x) = 2 or cos(x) = -1.5 have no real solutions because they exceed these bounds.
How do I check if my solutions are correct?β–Ύ
Substitute each answer back into the original equation. For cos(2x) = -1/2 with solution x = 3Ο€/8, check: cos(2 Γ— 3Ο€/8) = cos(3Ο€/4) = -√2/2 β‰ˆ -0.707, which matches -1/2 = -0.5. Wait, this needs verification against the exact decimal values.

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