Functions
A function assigns exactly one output value to each input value according to a specific rule. Written as f(x), the function takes an input x and transforms it into an output through operations like multiplication, addition, or squaring. Functions form the foundation of algebra and appear throughout GCSE mathematics, from Year 10 linear graphs to Year 13 polynomial sketching.
Why it matters
Functions model countless real-world relationships where one quantity depends on another. Mobile phone bills follow the function C(m) = 25 + 0.15m, where monthly cost depends on minutes used. Population growth follows exponential functions like P(t) = 1000 × 1.03t, predicting city populations over time. Engineers use quadratic functions to design bridges, calculating stress as S(x) = 0.5x² + 10x for beam loading. In physics, distance functions like d(t) = 5t² describe falling objects. Functions appear in GCSE specifications from Year 10 through A-level, connecting algebra to calculus and enabling students to solve complex problems across science, economics, and engineering disciplines.
How to solve functions
Functions — Slope & Intercepts
- A function assigns exactly one output to each input.
- Slope = (y₂ − y₁) / (x₂ − x₁) for any two points.
- x-intercept: set y = 0 and solve for x.
- y-intercept: set x = 0 and solve for y.
Example: Line through (1, 3) and (3, 7): slope = (7−3)/(3−1) = 2.
Worked examples
If f(x) = x + 2, find f(8)
Answer: 10
- Substitute x = 8 → f(8) = 8 + 2 = 10 — Replace x with 8 in the expression.
If f(x) = 5x + 7, find f(4)
Answer: 27
- Substitute x = 4 → f(4) = 5 x 4 + 7 = 20 + 7 = 27 — Multiply first, then add or subtract.
If f(x) = x² + 2, find f(2)
Answer: 6
- Calculate x² → 2² = 4 — 2 times 2 equals 4.
- Add 2 → 4 + 2 = 6 — f(2) = 4 + 2 = 6.
Common mistakes
- Confusing function notation: writing f(3) = x + 3 instead of f(3) = 3 + 3 = 6 when evaluating f(x) = x + 3
- Order of operations errors: calculating f(4) = 2 × 4 + 5 as 2 × 9 = 18 instead of 8 + 5 = 13
- Function composition mistakes: finding f(g(2)) by calculating f(2) + g(2) = 7 + 5 = 12 instead of first finding g(2) = 5, then f(5) = 11