Mean, Median & Mode
Mean, median, and mode are three measures of central tendency that describe the typical value within a data set. The mean represents the arithmetic average, the median identifies the middle value when data is arranged in order, and the mode indicates the most frequently occurring value. These statistical measures appear in Year 10 GCSE mathematics and form the foundation for more advanced statistical analysis.
Why it matters
Mean, median, and mode provide essential tools for interpreting real-world data across numerous fields. Market researchers use the median household income (£31,400 in the UK) rather than the mean because extreme wealth skews averages upward. Sports statisticians calculate mean goals per match to assess team performance, whilst fashion retailers identify the modal shoe size (size 6 for women) to optimise stock levels. Medical researchers compare median recovery times between treatments, and teachers analyse modal GCSE grades to understand class performance patterns. These measures help distinguish between different types of 'average' — the mean salary of £35,000 might seem typical, but if the median is £28,000, this reveals income inequality. Understanding when to use each measure becomes crucial for accurate data interpretation in economics, psychology, and scientific research.
How to solve mean, median & mode
Mean, Median & Mode
- Mean = sum of all values ÷ count.
- Median = middle value when sorted (average of two middles if even count).
- Mode = value that appears most often.
Example: Data: 3, 5, 5, 7, 10. Mean=6, Median=5, Mode=5.
Worked examples
The following heights in cm were collected: 3, 6, 9. Calculate the mean.
Answer: 6.0
- Add all the numbers together → 3 + 6 + 9 = 18 — Line up all 3 values and add them one by one. Think of collecting all the heights in cm into one big pile: the total is 18.
- Count how many numbers there are → n = 3 — Count each value in the list. We have 3 numbers. This is important because we'll divide by this count.
- Divide the total by the count → 183 = 6.0 — Mean = total / count = 18 / 3 = 6.0. If you could somehow even out everyone's height so they were all the same, that common height would be the mean.
- Verify: does mean x count = total? → 6.0 x 3 = 18.0 (= 18 ✓) — Always check: multiply the mean by the count. If you get back the total (or very close due to rounding), you're correct!
The following test scores were collected: 8, 8, 9, 12, 14. Calculate the mean.
Answer: 10.2
- Add all the numbers together → 8 + 8 + 9 + 12 + 14 = 51 — Line up all 5 values and add them one by one. Think of collecting all the test scores into one big pile: the total is 51.
- Count how many numbers there are → n = 5 — Count each value in the list. We have 5 numbers. This is important because we'll divide by this count.
- Divide the total by the count → 515 = 10.2 — Mean = total / count = 51 / 5 = 10.2. If the test was worth 100 points and everyone got the same score, they'd all have the mean.
- Verify: does mean x count = total? → 10.2 x 5 = 51.0 (= 51 ✓) — Always check: multiply the mean by the count. If you get back the total (or very close due to rounding), you're correct!
A survey collected these prices: 2, 7, 11, 12, 12, 20, 49. Calculate the median.
Answer: 12
- Put the numbers in order (smallest to largest) → 2, 7, 11, 12, 12, 20, 49 — The median is the middle value, so we need the numbers sorted. Like lining up kids by height to find the one in the middle.
- Count: 7 values (odd) → n = 7 (odd) — We have 7 values. This matters because: if odd, take the exact middle; if even, average the two middle values. With 7 values (odd), the middle position is 4.
- Find the middle value (position 4) → Median = 12 — Position 4 in the sorted list is 12. There are 3 values below it and 3 values above it -- it's right in the middle!
- Verify → Median = 12 ✓ — Check: 3 values below and 3 values above. The median sits right in the centre of the data.
Common mistakes
- Confusing mean and median calculations, such as finding the mean of 2, 4, 6, 8, 10 as 6 (the median) instead of 6 (which happens to be correct, but through wrong reasoning).
- Forgetting to arrange data in ascending order before finding the median, leading to selecting 15 as the median of 10, 15, 12, 18, 20 instead of the correct answer of 15.
- Assuming every data set has a mode, when sets like 1, 2, 3, 4, 5 have no repeated values and therefore no mode.
- Averaging the two middle values incorrectly for even-numbered data sets, such as finding the median of 3, 5, 7, 9 as 6.5 instead of 6.
- Including the mode frequency in calculations, mistakenly writing the mode of 2, 2, 2, 5, 8 as 6 (counting three 2s) rather than simply 2.